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Finite series
Powers
∑
k
=
1
n
k
=
n
⋅
(
n
+
1
)
2
∑
k
=
1
n
k
2
=
n
⋅
(
n
+
1
)
⋅
(
2
n
+
1
)
6
∑
k
=
1
n
k
3
=
n
2
⋅
(
n
+
1
)
2
2
2
Binomial coefficients
∑
k
=
0
n
(
n
k
)
=
2
n
∑
k
=
0
n
(
n
k
)
2
=
(
2
n
n
)
Harmonic series
1
+
1
2
+
.
.
.
+
1
n
≈
ln
(
n
)
+
0.5772
Infinite series
Taylor series
f
(
x
)
−
f
(
x
k
)
=
(
x
−
x
k
)
∂
f
∂
x
(
x
k
)
+
(
x
−
x
k
)
2
2
!
∂
2
f
∂
x
2
(
x
k
)
+
.
.
.
TIP
Using Taylor series, we can approximate smooth, differentiable functions.$.
Riemann zeta function
1
+
1
2
2
+
1
3
2
+
.
.
.
=
ζ
(
2
)
=
π
2
6
1
+
1
2
4
+
1
3
4
+
.
.
.
=
ζ
(
4
)
=
π
4
45